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7x^2+3x-306=0
a = 7; b = 3; c = -306;
Δ = b2-4ac
Δ = 32-4·7·(-306)
Δ = 8577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8577}=\sqrt{9*953}=\sqrt{9}*\sqrt{953}=3\sqrt{953}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{953}}{2*7}=\frac{-3-3\sqrt{953}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{953}}{2*7}=\frac{-3+3\sqrt{953}}{14} $
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